Perimeter of lawn = 2(length + breadth) =2 (75 + 45)m = 240 m ... Area of rectangular field including the foot path = (54 × 35) m 2 Let the width of the path be x m ... Let the length and breadth of a rectangular garden be 9x and 5x. Then, area of garden = (9x × 5x) m 2 = 45 x 2 m 2rectangular round edged broad-crested weirs, and triangular broad-crested or crump weirs. Among these weirs, the simplest is the square-edged weir (edge refers to the entrance from the approach channel) with rectangular cross section. The main advantages of rectangular broad-crested weirs with 90º upstream face slope include constant discharge A rectangular field has a breadth of 12 m. its length is 3 time as long as its breadth. what is the perimeter of the field? ... Step-by-step explanation: Length = 3x = 3 × 12 = 36 m and Breadth = x = 12 m. Length of fencing = Perimeter of the field. Perimeter = 2(Length + Breadth) = 2(36 + 12) = 96 m. ... of the top edge of the cylinder is ...The formula for the perimeter of a rectangle is (width + height) x 2, as seen in the figure below: This is the equivalent of adding all four sides, since opposite sides are of equal length by definition. Make sure the calculation is done using the same unit - the result will also be in that unit, e.g. mm, cm, meters, km, or in, ft, yd, miles.Solution (By Examveda Team) Let length and breadth of the rectangle are L and B respectively. Perimeter = 150 m. So, Area = L *B Given, Area / length = 1/30 L/LB = 1/30 B = 30. Perimeter = 2 (L +B) 150 = 2 (L +B) (L +B) = 75 L +30 = 150 L = 45 m. Length = 45 m. Related User Ask Questions Which of the following is not a primary function of a Bank?Apr 01, 2022 · Length of rectangle = 7 × 15 = 105cm Breadth of rectangle = 4 × 15 = 60cm Area of rectangle = 105 × 60 cm² = 6300 cm² Is the area of the wall. Question 42: Length of a rectangular field is 6 times its breadth. If the length of the field is 120cm, find the breadth and perimeter of the field. Solution: -- View Answer: 7). If the length of a rectangle decreases by 5 m and breadth increases by 3 m, then its area reduces 9 sq m. If length and breadth of this rectangle increased by 3 m and 2 m respectively, then its area increased by 67 sq m.December 11, 2015 ·. 1. The length and breadth of a rectangular field are in the ratio of 3:2. If the perimeter of the field is 80m, its breadth (in metres) is: (SSC CGL Prelim Exam. 1999) (a) 18 (b) 16. (c) 10 (d) 24. 2. The perimeter of the top of a rectangular table is 28m., whereas its area is 48m2.1. Find perimeter of rectangle whose length =6m8dm and breadth =4n6dm 2. Find the cost of fencing rectangle field 24n long and 18m wide at Rs. 6.25 per meter. 3. The length and breadth of rectangle field are in ratio 5:3. If its perimeter is 64m. Find the dimensions. 4. The cost of fencing a rectangle field at Rs. 14.60 per m is 1606.Area of the rectangular field = Length x Breadth = 200 m x 125 m = 25000 m 2 = 250 ares [Since 100 m 2 = 1 are] (ii) Length of the rectangular field =75 m 5 dm = (75 + 0.5) m = 75.5 m [Since 1 dm = 10 cm = 0.1 m] Breadth of the rectangular field = 120 m Therefore, Area of the rectangular field = Length x Breadth = 75.5 m x 120 mThings to try. In the figure at the top of the page, click on 'reset' and 'hide details'. Then drag the corners to create an arbitrary rectangle. Calculate the length of the diagonals. Click 'show details' to verify your answer. A rectangle has a height of 12 and a diagonal of 31. Find the width of the rectangle and use the animation or the ... The length of the rectangular field=45 m The width of the rectangular field=65 m The field covered by the house is a square with a side of 8 m. The area=8 2 =64 The area of the rectangular field=2,925-64 =2,861 sq m. Hence, the area of the rectangular field=2,861 sq m. Example 12. A rectangle has a length of 14 cm and its width is 4 cm smaller ...A field in the shape of an equilateral triangle with side 225 m is fenced with three rounds of rope. Another field, rectangular in shape, of length 200 m and breadth 125 m is fenced with two rounds of rope. Which field requires more rope and by how much?...

The length and breadth of a rectangular field are in the ratio 9 : 5. If the area of the field is 14580 square metres, find the cost of surrounding the field with a fence at the rate of ₹3·25 per metre. Solution: Let the length = 9x and the breadth = 5x Area = l × b ⇒ 14580 = 9x × 5x ⇒ 45x 2 = 14580Before we can find the dimensions of the rectangle, we need find w first. Here's how: 1) Write an equation that relates 45cm 2, w+4 and w. To do so, we know that the area of the rectangle, 45cm 2 can be found by multiplying w with w+4. Aug 30, 2021 · A farmer has a rectangular field of length and breadth 240 m and 180 m respectively. He wants to fence it with 3rounds of rope as shown in figure 10.4.What is the total length of rope he must use? Form a quadratic equation by taking the length of the field as x and solve it to find the length and breadth of the field. the length and breadth are A) (205m, 80m) B) (50m, 40m) C) maths. The ratio between length and breath of rectangular field is 5:3. If the length is 120 cm,find the breadth of the field . MathAnswer:96 meterStep-by-step explanation:Length = 3x = 3 × 12 = 36 m and Breadth = x = 12 m. Length of fencing = Perimeter of the field. Perimeter = 2(Length + B… Answer (1 of 5): Let X = width and Let Y = height. Then 1) 2X + 2 Y =210 and 2) X/Y = 4/3 or 3) X = (4/3)Y From 1) and 3) 2(4/3)Y + 2Y = 210 therefore (8/3)Y + 2Y =210 the multiply both sides by 3 to get 8Y + 6Y =630 14Y = 630 divide by 7 to get 2Y = 90 Y = 45 from 3) X = (4/3) Y so X = 6...Apr 17, 2021 · Length of inner rectangle = 8m Breadth of inner rectangle = 5m Area of inner rectangle = l x b = 8 × 5 = 40m 2:. Area of the verandah = (Area of outer figure) – (Area of inner figure) = 108 – 40 = 68m 2. Question 5. The length of a rectangular park is 700 m and its breadth is 300 m. Two crossroads, each of width 10 m, cut the centre of a ... It is given that the length (l) of the rectangle = 12 cm, and width (w) = 8 cm. On substituting the values in the formula, we get, Perimeter of rectangle = 2(l + w) = 2(12 + 8) = 2 × 20 = 40 cm. Therefore, the perimeter of the rectangle is 40 cm. Example 2: What is the perimeter of a rectangle with a length of 15 m and a breadth of 9 m?A rectangular floor 45 in long and 12 m broad is to be paved exactly with square tiles, of side 60 cm. Find the total number of tiles required to pave it. ... The length and breadth of a rectangular field are in the ratio 8 : 5. A 2m wide path runs all around outside the field....

The length and breadth of a rectangular piece of land are in the ratio 5: 3. If the total cost of fencing it at the rate of 2 4 per meter is 9 6 0 0, find its: (i) length and breadth, (ii) area, (iii) cost of levelling at the rate of 6 0 per m 2.Jul 05, 2018 · Length of a field (l) = 200 m Breadth (b) = 150 m Length of plot = 50 m and breadth = 40 m Depth of plot = 7 m. Question 15. A field is in the form of a rectangle of length 18 m and width 15 m. A pit, 7.5 m long, 6 m broad and 0.8 m deep, is dug in a comer of the field and the earth taken out is spread- over the remaining area of the field. Area of the rectangular field = Length x Breadth = 200 m x 125 m = 25000 m 2 = 250 ares [Since 100 m 2 = 1 are] (ii) Length of the rectangular field =75 m 5 dm = (75 + 0.5) m = 75.5 m [Since 1 dm = 10 cm = 0.1 m] Breadth of the rectangular field = 120 m Therefore, Area of the rectangular field = Length x Breadth = 75.5 m x 120 mBreadth of Rectangle given length and perimeter is the measurement or extent of something from side to side; the lesser of two dimensions of the rectangle is calculated using Breadth = (Perimeter-2* Length)/2.To calculate Breadth of Rectangle given length and perimeter, you need Perimeter (P) & Length (L).With our tool, you need to enter the respective value for Perimeter & Length and hit the ...Transcript. Example 7 Pinky runs around a square field of side 75 m, Bob runs around a rectangular field with length 160 m and breadth 105 m. Who covers more distance and by how much? Side of square park = a = 75 m Length of Rectangular park = 160 m Breadth of Rectangular park = 105 m Perimeter of square park = 4a = 4 × 75 = 300 m Distance ...Dec 19, 2014 · 126. wap to input number and check whether the given no. is prime or composite. cls input "enter any number"; n c = 0 for i = 1 to n if n mod i = 0 then c = c + 1 next i if c = 2 then print n; "is prime number" else print n; "is composite number" end if end using sub procedure declare sub prime (n) input "enter any number"; n call prime (n) end sub prime (n) c = 0 for i = 1 to n if n mod i = 0 ... Rectangular Field Area. Where: = Area of the field (sq. ft) = Length of the field (ft) = Width of the field (ft) Triangular Field Area. Where: = Area of the field (sq. ft) = Length of the Base of the field (ft) = Distance from the base to the top of the field at a 90° from the base (ft) Circular Field Area. Where: = Area of the field (sq. ft ... The field is rectangular in shape. Given, length(l) = 90 m and breadth(b) = 45 m Distance travelled by the player is the perimeter of the rectangular ground. ∴ Total distance travelled = 2(l + b) = 2(90 + 45) = 270 mSolution Verified by Toppr Given: Length of the rectangular field =110 m Breadth of the rectangular field =85 m Perimeter of the rectangular field =2(l+b) =2(110+85)=2×195 Perimeter of the rectangular field =390 m 2 Cost to fence the field per metre = Rs. 25 Cost to fence the field 390 metre = Rs. 25×390=Rs.9,750A path 5 m wide runs along the inside of the rectangular field. The length of the rectangular field is three times the breadth of the field. If the area of the path is 500 m 2 then find the length and breadth of the fieldExamples based on Finding the cost of fencing of a rectangular field. Example 1. Find the cost of fencing of a rectangular field 65 m long and 55 m wide at ₹ 10 per metre? Explanation. Length of the field = 65 m Breadth of the field = 55 m Perimeter of the field = 2 ( l+b ) units Perimeter of the field = 2 ( 65 + 55 ) m...

A path 5 m wide runs along the inside of the rectangular field. The length of the rectangular field is three times the breadth of the field. If the area of the path is 500 m 2 then find the length and breadth of the field.1. Find perimeter of rectangle whose length =6m8dm and breadth =4n6dm 2. Find the cost of fencing rectangle field 24n long and 18m wide at Rs. 6.25 per meter. 3. The length and breadth of rectangle field are in ratio 5:3. If its perimeter is 64m. Find the dimensions. 4. The cost of fencing a rectangle field at Rs. 14.60 per m is 1606.A rectangular field has a breadth of 12 m. its length is 3 time as long as its breadth. what is the perimeter of the field? ... Step-by-step explanation: Length = 3x = 3 × 12 = 36 m and Breadth = x = 12 m. Length of fencing = Perimeter of the field. Perimeter = 2(Length + Breadth) = 2(36 + 12) = 96 m. ... of the top edge of the cylinder is ...Example 20 A rectangular park is 45 m long and 30 m wide. A path 2.5 m wide is constructed outside the park. Find the area of the path.Here, Area of path = Area of larger rectangle − Area of smaller rectangleFinding length and breadth of both rectanglesSmaller rectangle Length ofA path 5 m wide runs along the inside of the rectangular field. The length of the rectangular field is three times the breadth of the field. If the area of the path is 500 m 2 then find the length and breadth of the field.Find the cost of fencing a rectangular park of length 350 m and breadth 250 mat the rate of Rs. 18.50 per meter. Verified. 168.3k+ views. Hint: To solve this question, we will use the formula of perimeter of a rectangle. The perimeter of a rectangle is given by, Perimeter = 2 (l + b), where l is the length and b is the breadth of the rectangle.Sep 21, 2018 · Transcript. Example 1 Length and breadth of a rectangular field are 50 m and 15 m respectively. Find the ratio of the length to the breadth of the field. And the length of rectangular field = 80 m According to question, Perimeter of rectangular field = Perimeter of square field = 4 side m Now Area of Square field = = = 3600 m 2 And Area of Rectangular field = length breadth = 80 40 = 3200 Hence, area of square field is larger. Question 2. Area of rectangle = ( length x breadth ) = ( 6 x 7 ) cm² = 42 cm². Hence, the area of rectangle is 42 cm². Perimeter And Area Questions For Class 6 - Finding cost of fencing of a rectangular field. Question 9. Find the cost of fencing of a rectangular field 20 m long and 35 m wide at ₹ 6 per metre. Explanation. Length of the field = 20 m ...Shikha runs around a square of side 75 mtherefore Perimeter of the square = 4 times side = 4 times 75 = 300 mPriya runs around a rectangle with length, L =60 m and breadth, B=45 mtherefore Perimeter of the rectangle = 2 (L+ B) = 2(60 +45) = 210 mbecause 210 lt 300Rightarrow Priya covers the smaller distance. | Snapsolve 45 L1Difficulty 2 QTags Probability QCreator AYUSH PANDEY Q56, SBI clerk pre 2 (2019) Q3. A rectangular field was fenced at 4 Rs./meter and ratio of breadth to length of field is 9 : 4. If total cost of fencing was Rs. 208, then find area of the rectangular field? (a) 144m² (b) 72m² (c) 180m² (d) 108m² (e)36m² L1Difficulty 2 QTags 2D ...The length and breadth of a rectangular sheet are 16.2 cm and 10.1 cm, respectively. ... Question 4 45° Figure 4 Figure 4 shows t wo particles 4 and B of mass 5 kg and 4 kg. A: ... Electric field (E) : It is defined as the number of lines passing through a field. Electric force (...Meenu wants to put a lace border all around a rectangle table cover 2 m long and 1 m wide. Find the length of the lace required by Meenu. (a) 3 m (b) 4 m (c) 5 m (d) 6m. Answer. Answer: (d) Hint: Length of the lace = 2(2 + 1) = 6 mArea is measured in square units such as square inches, square feet or square meters. To find the area of a rectangle, multiply the length by the width. The formula is: A = L * W where A is the area, L is the length, W is the width, and * means multiply. A square is a rectangle with 4 equal sides. To find the area of a square, multiply the ... Breadth of Rectangle given length and perimeter is the measurement or extent of something from side to side; the lesser of two dimensions of the rectangle is calculated using Breadth = (Perimeter-2* Length)/2.To calculate Breadth of Rectangle given length and perimeter, you need Perimeter (P) & Length (L).With our tool, you need to enter the respective value for Perimeter & Length and hit the ...Click Home tab > Draw panel > Rectangle. Find Specify the first corner of the rectangle. Specify the other corner of the rectangle. By Length and Width Click Home tab > Draw panel > Rectangle. Find Specify the first corner of the rectangle. Enter D for Dimensions. Enter the length. Enter the width. Specify the other corner. Note: You are restricted by the length and width values. By Area Click ... Jul 05, 2018 · Length of a field (l) = 200 m Breadth (b) = 150 m Length of plot = 50 m and breadth = 40 m Depth of plot = 7 m. Question 15. A field is in the form of a rectangle of length 18 m and width 15 m. A pit, 7.5 m long, 6 m broad and 0.8 m deep, is dug in a comer of the field and the earth taken out is spread- over the remaining area of the field. ...

Length and breadth of a rectangular field are in the ratio 5 : 4. If the width of the field is 36 m, what is its length? - Mathematics. ... 45 m Length:Breadth = 5:4 Let x be any number such that the length and the breadth are 5x and 4x, respectively. Now , 4x= 36 x = `36/4` = 9The breadth is \[30m\] and \[30 = 2 \times 3 \times 5\]. To find the length of the longest rod which can measure the length and breadth of the field exactly we need to find the H.C.F of the length and breadth of the rectangle because H.C.F. is the greatest number which divides each of the two numbers.The area of a rectangular field is 3375 m 2 and its length and breadth are in the ratio 5:3. Find the breadth ? A)125m B)45m C)225m D)65m. Answer. B)45m Explanation : 5x × 3x = 3375 15x 2 = 3375 x 2 = 3375/15 = 225 x = 15 3x = 3*15 = 45. The perimeter of a square is twice the perimeter of a rectangle. ... The area of a square is 7sqm less than ...Solution Verified by Toppr Given: Length of the rectangular field =110 m Breadth of the rectangular field =85 m Perimeter of the rectangular field =2(l+b) =2(110+85)=2×195 Perimeter of the rectangular field =390 m 2 Cost to fence the field per metre = Rs. 25 Cost to fence the field 390 metre = Rs. 25×390=Rs.9,750The formula for the perimeter of a rectangle is (width + height) x 2, as seen in the figure below: This is the equivalent of adding all four sides, since opposite sides are of equal length by definition. Make sure the calculation is done using the same unit - the result will also be in that unit, e.g. mm, cm, meters, km, or in, ft, yd, miles.Ex 11.4, 7 Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find (i) the area covered by the roads. Our figure looks like= 45 m 2 Rate of cementing the verandah = Rs 80 per m 2 ... The length and breadth of a rectangular field are in the ratio 5 : 3 and its perimeter is 480 m. The area of the field is (a) 7200 m 2 (b) 13500 m 2 (c) 15000 m 2 (d) 54000 m 2. Answer:Ans 4 May Ques 10 The length of a rectangular field is thrice its breadth If the from ACCOUNTS 1-21 at Indian Institute Of Management, Indore ... Ans 4 May Ques 10 The length of a rectangular field is thrice its breadth If the. ... Ans. 40 45 30.Jul 27, 2018 · According to the stipulations from FIFA, a football field dimension should have specific minimum and maximum dimensions: – The length of touchline has to be minimum of 90 metres (100 yds) and maximum of 120 metres (130 yds). – The width of goal-line has to be minimum of 45 metres (50 yds) and maximum 90 meters (100 yds). Jul 27, 2018 · According to the stipulations from FIFA, a football field dimension should have specific minimum and maximum dimensions: – The length of touchline has to be minimum of 90 metres (100 yds) and maximum of 120 metres (130 yds). – The width of goal-line has to be minimum of 45 metres (50 yds) and maximum 90 meters (100 yds). Given: Length of the rectangular field =110 mBreadth of the rectangular field =85 mPerimeter of the rectangular field =2(l+b)=2(110+85)=2×195Perimeter of the rectangular field =390 m 2Cost to fence the field per metre = Rs. 25Cost to fence the field 390 metre = Rs. 25×390=Rs.9,750∴ Cost of fencing the field =Rs.9750. Breadth $= 2 x = 2 (45) = 90\ m$ Area of the rectangle $=$ Length $\times$ Breadth $=135\times90\ m^2$ $=12150\ m^2$ The area of the rectangle is $12150\ m^2$. 1. Related Doubts. The length and breadth of a rectangular field are in the rate you 5: 2: if the perimeter of the field is 140 metre find the area of the rectangleJul 05, 2018 · Length of a field (l) = 200 m Breadth (b) = 150 m Length of plot = 50 m and breadth = 40 m Depth of plot = 7 m. Question 15. A field is in the form of a rectangle of length 18 m and width 15 m. A pit, 7.5 m long, 6 m broad and 0.8 m deep, is dug in a comer of the field and the earth taken out is spread- over the remaining area of the field. The formula for the perimeter of a rectangle is (width + height) x 2, as seen in the figure below: This is the equivalent of adding all four sides, since opposite sides are of equal length by definition. Make sure the calculation is done using the same unit - the result will also be in that unit, e.g. mm, cm, meters, km, or in, ft, yd, miles.3. Through a rectangular field of sides 90 m x 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the center of the field. If the width of the roads is 3 m, find the total area covered by the two roads. Solution: Given length of rectangular field = 90m. Breadth of rectangular field = 60mThe length and the breadth of a rectangular field 128 m, find the dimensions are in the ratio 5: 3. If its perimeter is of the field. 4. The cost of fencing 23 a rectangular field at 18 per metre is 1980. If the width of the field is m, find its length. 5. The length and the breadth of field at 25 a rectangular field are in the ratio 7: 4Ex 11.4, 7 Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find (i) the area covered by the roads. Our figure looks like...

The length and breadth of a rectangular field are in the ratio 5 : 4. If its perimeter is 108 m, find the dimensions of the field. Answer: Let the length of the rectangle be 5x m. Breadth of the rectangle = 4x m Perimeter of the rectangle = 2(Length + Breadth) ... 45 m 2 (d) 120 m 2.Square calculator will give the area, perimeter and diagonal length of a square. OUput : Three positive real numbers or variables as the perimeter, area and diagonal length of a square and corresponding units after that. P = 4× a P = 4 × a where a a is the length of the side of square. Rectangular Field Area. Where: = Area of the field (sq. ft) = Length of the field (ft) = Width of the field (ft) Triangular Field Area. Where: = Area of the field (sq. ft) = Length of the Base of the field (ft) = Distance from the base to the top of the field at a 90° from the base (ft) Circular Field Area. Where: = Area of the field (sq. ft ...Dec 14, 2021 · 1. The length and breadth of a rectangular field are in the ratio 9:5. If the area of the field is 14580 square metre, find the cost of surrounding the field with a fence at the rate of 33.25 per metre. A rectangle is 16 mbym. Find a side of the square whose area canla Square calculator will give the area, perimeter and diagonal length of a square. OUput : Three positive real numbers or variables as the perimeter, area and diagonal length of a square and corresponding units after that. P = 4× a P = 4 × a where a a is the length of the side of square. Oct 01, 2020 · The area of a rectangular field is 250 m 2. If the breadth of the field is 10 m, find its length. If the breadth of the field is 10 m, find its length. (a) 25 m Answer:96 meterStep-by-step explanation:Length = 3x = 3 × 12 = 36 m and Breadth = x = 12 m. Length of fencing = Perimeter of the field. Perimeter = 2(Length + B… Rectangular Field Area. Where: = Area of the field (sq. ft) = Length of the field (ft) = Width of the field (ft) Triangular Field Area. Where: = Area of the field (sq. ft) = Length of the Base of the field (ft) = Distance from the base to the top of the field at a 90° from the base (ft) Circular Field Area. Where: = Area of the field (sq. ft ...Solution : Let the length and breadth of the field be 9x and 5x respectively. Area of the field = 14580 sq.m. We know that, The area of a rectangle of length l and breadth b is l × b. Therefore, Area of the field = ( 9 x) × ( 5 x) 14580 = 45 x 2 14580 45 = x 2 324 = x 2 x = 18 So, length (l) = 9 ( 18) = 162 m Breadth (b) = 5 ( 18) = 90 mClick Home tab > Draw panel > Rectangle. Find Specify the first corner of the rectangle. Specify the other corner of the rectangle. By Length and Width Click Home tab > Draw panel > Rectangle. Find Specify the first corner of the rectangle. Enter D for Dimensions. Enter the length. Enter the width. Specify the other corner. Note: You are restricted by the length and width values. By Area Click ... Jul 18, 2018 · Let the length and breadth of a rectangular garden be 9x and 5x. Then, area of garden = (9x × 5x) m 2 = 45 x 2 m 2 Length of park excluding the path = (9x – 7) m The length of the rectangular field=45 m The width of the rectangular field=65 m The field covered by the house is a square with a side of 8 m. The area=8 2 =64 The area of the rectangular field=2,925-64 =2,861 sq m. Hence, the area of the rectangular field=2,861 sq m. Example 12. A rectangle has a length of 14 cm and its width is 4 cm smaller ...9. A path 5 m wide runs along inside a rectangular field. The length of the rectangular field is three times the breadth of the field. If the area of the path is 500 m², then find the length and breadth of the field. Solution: Let l be the length of the field, breadth of the field is b. Breadth of the path = 5 m. The area of the path is 500 m².And Area of Rectangular field = length * breadth = 80 * 40 = 3200 m 2. Hence, area of square field is larger. ... The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m 2 is Rs4. Answer: Here, ......

Answer (1 of 5): Length of rectangle be L Breadth of rectangle be B Perimeter of rectangle be P Area of rectangle be A P = 150cm L/B = 3/2 L = 3x B = 2x Where x is any constant to be multiplied to get the correct length and breadth of rectangle. P = 2(L+B) 150 = 2(3x+2x) 75 = 5x x = 1...3. Through a rectangular field of sides 90 m x 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the center of the field. If the width of the roads is 3 m, find the total area covered by the two roads. Solution: Given length of rectangular field = 90m. Breadth of rectangular field = 60mBulbul runs around a rectangular park with length 60 m and breadth 45 m. Who covers less distance? Answer: Given that, Length of the square park = 75m Length and breadth of the rectangular park is 60 m and 45m respectively . Therefore, The perimeter of the square park = 4 75 =300 mBulbul runs around a rectangular park with length 60 m and breadth 45 m. Who covers less distance? Answer: Given that, Length of the square park = 75m Length and breadth of the rectangular park is 60 m and 45m respectively . Therefore, The perimeter of the square park = 4 75 =300 mHere it is given that the length of a rectangular field is thrice its breadth Now, let the breadth be x and length be y Then the situation can be mathematically represented as Perimeter is 120 cm We have to find the length of the field Perimeter of rectangle = 2 ( length + breadth) = Therefore, y = 3 × 15 = 45 So, length of the field will be 45 cm.Perimeter of lawn = 2(length + breadth) =2 (75 + 45)m = 240 m ... Area of rectangular field including the foot path = (54 × 35) m 2 Let the width of the path be x m ... Let the length and breadth of a rectangular garden be 9x and 5x. Then, area of garden = (9x × 5x) m 2 = 45 x 2 m 2Answer: The width of the playing field = 45 ft. length of playing fiels = 86ft. Step-by-step explanation: Step 1. Perimeter of rectangular field is given as 2 ( L+ b) Let the width be represented as x. such that the length = 41 ft longer than the width be x+ 41. To find the length and breadth . Step 2. Perimeter = 2( L+ b)= 2l + 2bAnd the length of rectangular field, l = 80 m (Given) According to question, Perimeter of rectangular field = Perimeter of square field 2(l+b) = 4×Side (using formulas) 2(80+b) = 4×60 160+2b = 240 b = 40 Breadth of the rectangle is 40 m. Now, Area of Square field = (side)2 = (60)2 = 3600 m2 And Area of Rectangular field = length×breadth = 80×40 Question. 39 The perimeter of-a-rectangle becomes_____times its original perimeter, if its length and breadth are doubled. Solution. 2 times Perimeter of a rectangle with length l and breadth b = 2(l + b) If the length and the breadth are doubled, then the new perimeter = 2(2l + 2b) = 2[2(l + b)]Nov 29, 2021 · The diagonal of a rectangle is a segment that connects two opposite vertices of a rectangle. Let's calculate the diagonal length of the exemplary rectangle: Choose the length of the rectangle - for example, a = 5 cm. Decide on the width of the rectangle - for example, b = 6 cm. Calculate a to the power of two: a² = 25 cm². Sep 21, 2018 · Transcript. Example 1 Length and breadth of a rectangular field are 50 m and 15 m respectively. Find the ratio of the length to the breadth of the field. The length and breadth of a rectangular piece of land are in the ratio 5: 3. If the total cost of fencing it at the rate of 2 4 per meter is 9 6 0 0, find its: (i) length and breadth, (ii) area, (iii) cost of levelling at the rate of 6 0 per m 2.Therefore, length of rectangle is 21.5 m and the area is 344 m2. Question 2: Solution: The length of a rectangular park = 2(its breadth) Perimeter = 840 m (Given) Let x be the breadth of a rectangular park then, length of a rectangular park is 2x m. We know, Perimeter of rectangle = 2(Length + Breadth) 840 = 2(Length + Breadth) 840 = 2(2x + x) ...

It is given that the length (l) of the rectangle = 12 cm, and width (w) = 8 cm. On substituting the values in the formula, we get, Perimeter of rectangle = 2(l + w) = 2(12 + 8) = 2 × 20 = 40 cm. Therefore, the perimeter of the rectangle is 40 cm. Example 2: What is the perimeter of a rectangle with a length of 15 m and a breadth of 9 m?Dec 05, 2020 · Length of the field = 50m. Breadth of the field = 45m. Answer:-. Length of the field = 2* (l+b) 2* (50+45) 2*95. = 190m. Cost of fencing per metre = ₹4 per m. Cost of fencing 190m = 190x4. the length of a rectangular field is twice it's breadth. if the perimeter of the rectangular field 150. find the length and breadth of the rectangular park? ( 5 ) 1 Rating 1 views .A rectangle is a four-sided flat shape where every angle is a right angle (90°). the little squares in each corner mean "right angle". Each internal angle is 90°. Opposite sides are parallel and of equal length (so it is a Parallelogram ). Play with a rectangle: The area of a rectangular field is 11.025 square metre. If its breadth measures 4.5 metre, then calculate its length.The perimeter of a rectangular sheet is 100 cm. If the length is 35 cm, find its breadth. Also find the area. 5. The area of a square park is the same as of a rectangular park. If the side of the square park is 60 m and the length of the rectangular park is 90 m, find the breadth of the rectangular park. 6. A wire is in the shape of a rectangle.A path 5 m wide runs along the inside of the rectangular field. The length of the rectangular field is three times the breadth.of the field. If the area of the path is 500 m 2 then find the length and breadth of the field. Solution: Let the length of the rectangular field = 'L' m Breadth of the rectangular field = = 'B' m45 L1Difficulty 2 QTags Probability QCreator AYUSH PANDEY Q56, SBI clerk pre 2 (2019) Q3. A rectangular field was fenced at 4 Rs./meter and ratio of breadth to length of field is 9 : 4. If total cost of fencing was Rs. 208, then find area of the rectangular field? (a) 144m² (b) 72m² (c) 180m² (d) 108m² (e)36m² L1Difficulty 2 QTags 2D ...Dec 19, 2014 · 126. wap to input number and check whether the given no. is prime or composite. cls input "enter any number"; n c = 0 for i = 1 to n if n mod i = 0 then c = c + 1 next i if c = 2 then print n; "is prime number" else print n; "is composite number" end if end using sub procedure declare sub prime (n) input "enter any number"; n call prime (n) end sub prime (n) c = 0 for i = 1 to n if n mod i = 0 ... Ex 11.4, 7 Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find (i) the area covered by the roads. Our figure looks likeIf the length of a rectangular field is increased by 14 m and breadth is decreased by 6 m. Then its area remains the same. If the length is decreased by 14 m and breadth increased by 10 m then also area remains the same. The length and breadth of rectangle are. Shreya estimated the cost of painting the four walls of her old room to be Rs. 600.Find the cost of fencing a rectangular park of length 350 m and breadth 250 mat the rate of Rs. 18.50 per meter. Verified. 168.3k+ views. Hint: To solve this question, we will use the formula of perimeter of a rectangle. The perimeter of a rectangle is given by, Perimeter = 2 (l + b), where l is the length and b is the breadth of the rectangle.A path 5 m wide runs along the inside of the rectangular field. The length of the rectangular field is three times the breadth of the field. If the area of the path is 500 m 2 then find the length and breadth of the field...

Example 4 A farmer has a rectangular field of length and breadth 240 m and 180 m respectively. He wants to fence it with 3 rounds of rope as shown in figure 10.4. What is the total length of rope he must use? Length of rectangular field = 240 m Length of rectangular field = 180 m Perimeter of fGiven: Length of the rectangular field =110 mBreadth of the rectangular field =85 mPerimeter of the rectangular field =2(l+b)=2(110+85)=2×195Perimeter of the rectangular field =390 m 2Cost to fence the field per metre = Rs. 25Cost to fence the field 390 metre = Rs. 25×390=Rs.9,750∴ Cost of fencing the field =Rs.9750. Bulbul runs around a rectangular park with length 60 m and breadth 45 m. Who covers less distance? Answer: Given that, Length of the square park = 75m Length and breadth of the rectangular park is 60 m and 45m respectively . Therefore, The perimeter of the square park = 4 75 =300 mThe breadth is \[30m\] and \[30 = 2 \times 3 \times 5\]. To find the length of the longest rod which can measure the length and breadth of the field exactly we need to find the H.C.F of the length and breadth of the rectangle because H.C.F. is the greatest number which divides each of the two numbers.Dec 06, 2021 · Transcript. Example 20 A rectangular park is 45 m long and 30 m wide. A path 2.5 m wide is constructed outside the park. Find the area of the path. Here, Area of path = Area of larger rectangle − Area of smaller rectangle Finding length and breadth of both rectangles Smaller rectangle Length of smaller rectangle = 45 m Breadth of smaller ... Area of rectangle B = length × breadth = lb. Calculation: Let the length and breadth of rectangle B be 'l' and 'b' units respectively. Length of rectangle A = (4/5)l. Breadth of rectangle A = (1/2)b. Area of rectangle A = 4l/5 × b/2 = (2/5)lb. Required percentage = [(2/5)lb]/lb × 100 = 40%. ∴ The area of rectangle A is 40% of the ...Therefore, length of rectangle is 21.5 m and the area is 344 m2. Question 2: Solution: The length of a rectangular park = 2(its breadth) Perimeter = 840 m (Given) Let x be the breadth of a rectangular park then, length of a rectangular park is 2x m. We know, Perimeter of rectangle = 2(Length + Breadth) 840 = 2(Length + Breadth) 840 = 2(2x + x) Transcript. Example 1 Length and breadth of a rectangular field are 50 m and 15 m respectively. Find the ratio of the length to the breadth of the field.Examples based on Finding the cost of fencing of a rectangular field. Example 1. Find the cost of fencing of a rectangular field 65 m long and 55 m wide at ₹ 10 per metre? Explanation. Length of the field = 65 m Breadth of the field = 55 m Perimeter of the field = 2 ( l+b ) units Perimeter of the field = 2 ( 65 + 55 ) mClick Home tab > Draw panel > Rectangle. Find Specify the first corner of the rectangle. Specify the other corner of the rectangle. By Length and Width Click Home tab > Draw panel > Rectangle. Find Specify the first corner of the rectangle. Enter D for Dimensions. Enter the length. Enter the width. Specify the other corner. Note: You are restricted by the length and width values. By Area Click ... Solution : Let the length and breadth of the field be 9x and 5x respectively. Area of the field = 14580 sq.m. We know that, The area of a rectangle of length l and breadth b is l × b. Therefore, Area of the field = ( 9 x) × ( 5 x) 14580 = 45 x 2 14580 45 = x 2 324 = x 2 x = 18 So, length (l) = 9 ( 18) = 162 m Breadth (b) = 5 ( 18) = 90 mArea is measured in square units such as square inches, square feet or square meters. To find the area of a rectangle, multiply the length by the width. The formula is: A = L * W where A is the area, L is the length, W is the width, and * means multiply. A square is a rectangle with 4 equal sides. To find the area of a square, multiply the ... The field is rectangular in shape. Given, length(l) = 90 m and breadth(b) = 45 m Distance travelled by the player is the perimeter of the rectangular ground. ∴ Total distance travelled = 2(l + b) = 2(90 + 45) = 270 mDimensions and Markings for the Field Hockey Pitch. Pitch boundary: The pitch on which field hockey is played has a length of 299 feet, 10 inches (91.4 meters) and a width of 180 feet, 5 inches (55.0 meters). This boundary is marked on the turf and the shorter lines are called backlines. Centerline: Breadth $= 2 x = 2 (45) = 90\ m$ Area of the rectangle $=$ Length $\times$ Breadth $=135\times90\ m^2$ $=12150\ m^2$ The area of the rectangle is $12150\ m^2$. 1. Related Doubts. The length and breadth of a rectangular field are in the rate you 5: 2: if the perimeter of the field is 140 metre find the area of the rectangle...