Length and breadth of a rectangular field are in the ratio 5 : 4. If the width of the field is 36 m, what is its length? - Mathematics. ... 45 m Length:Breadth = 5:4 Let x be any number such that the length and the breadth are 5x and 4x, respectively. Now , 4x= 36 x = 36/4 = 9The breadth is $30m$ and $30 = 2 \times 3 \times 5$. To find the length of the longest rod which can measure the length and breadth of the field exactly we need to find the H.C.F of the length and breadth of the rectangle because H.C.F. is the greatest number which divides each of the two numbers.The area of a rectangular field is 3375 m 2 and its length and breadth are in the ratio 5:3. Find the breadth ? A)125m B)45m C)225m D)65m. Answer. B)45m Explanation : 5x × 3x = 3375 15x 2 = 3375 x 2 = 3375/15 = 225 x = 15 3x = 3*15 = 45. The perimeter of a square is twice the perimeter of a rectangle. ... The area of a square is 7sqm less than ...Solution Verified by Toppr Given: Length of the rectangular field =110 m Breadth of the rectangular field =85 m Perimeter of the rectangular field =2(l+b) =2(110+85)=2×195 Perimeter of the rectangular field =390 m 2 Cost to fence the field per metre = Rs. 25 Cost to fence the field 390 metre = Rs. 25×390=Rs.9,750The formula for the perimeter of a rectangle is (width + height) x 2, as seen in the figure below: This is the equivalent of adding all four sides, since opposite sides are of equal length by definition. Make sure the calculation is done using the same unit - the result will also be in that unit, e.g. mm, cm, meters, km, or in, ft, yd, miles.Ex 11.4, 7 Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find (i) the area covered by the roads. Our figure looks like= 45 m 2 Rate of cementing the verandah = Rs 80 per m 2 ... The length and breadth of a rectangular field are in the ratio 5 : 3 and its perimeter is 480 m. The area of the field is (a) 7200 m 2 (b) 13500 m 2 (c) 15000 m 2 (d) 54000 m 2. Answer:Ans 4 May Ques 10 The length of a rectangular field is thrice its breadth If the from ACCOUNTS 1-21 at Indian Institute Of Management, Indore ... Ans 4 May Ques 10 The length of a rectangular field is thrice its breadth If the. ... Ans. 40 45 30.Jul 27, 2018 · According to the stipulations from FIFA, a football field dimension should have specific minimum and maximum dimensions: – The length of touchline has to be minimum of 90 metres (100 yds) and maximum of 120 metres (130 yds). – The width of goal-line has to be minimum of 45 metres (50 yds) and maximum 90 meters (100 yds). Jul 27, 2018 · According to the stipulations from FIFA, a football field dimension should have specific minimum and maximum dimensions: – The length of touchline has to be minimum of 90 metres (100 yds) and maximum of 120 metres (130 yds). – The width of goal-line has to be minimum of 45 metres (50 yds) and maximum 90 meters (100 yds). Given: Length of the rectangular field =110 mBreadth of the rectangular field =85 mPerimeter of the rectangular field =2(l+b)=2(110+85)=2×195Perimeter of the rectangular field =390 m 2Cost to fence the field per metre = Rs. 25Cost to fence the field 390 metre = Rs. 25×390=Rs.9,750‬∴ Cost of fencing the field =Rs.9750. Breadth $= 2 x = 2 (45) = 90\ m$ Area of the rectangle $=$ Length $\times$ Breadth $=135\times90\ m^2$ $=12150\ m^2$ The area of the rectangle is $12150\ m^2$. 1. Related Doubts. The length and breadth of a rectangular field are in the rate you 5: 2: if the perimeter of the field is 140 metre find the area of the rectangleJul 05, 2018 · Length of a field (l) = 200 m Breadth (b) = 150 m Length of plot = 50 m and breadth = 40 m Depth of plot = 7 m. Question 15. A field is in the form of a rectangle of length 18 m and width 15 m. A pit, 7.5 m long, 6 m broad and 0.8 m deep, is dug in a comer of the field and the earth taken out is spread- over the remaining area of the field. The formula for the perimeter of a rectangle is (width + height) x 2, as seen in the figure below: This is the equivalent of adding all four sides, since opposite sides are of equal length by definition. Make sure the calculation is done using the same unit - the result will also be in that unit, e.g. mm, cm, meters, km, or in, ft, yd, miles.3. Through a rectangular field of sides 90 m x 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the center of the field. If the width of the roads is 3 m, find the total area covered by the two roads. Solution: Given length of rectangular field = 90m. Breadth of rectangular field = 60mThe length and the breadth of a rectangular field 128 m, find the dimensions are in the ratio 5: 3. If its perimeter is of the field. 4. The cost of fencing 23 a rectangular field at 18 per metre is 1980. If the width of the field is m, find its length. 5. The length and the breadth of field at 25 a rectangular field are in the ratio 7: 4Ex 11.4, 7 Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find (i) the area covered by the roads. Our figure looks like...
Example 4 A farmer has a rectangular field of length and breadth 240 m and 180 m respectively. He wants to fence it with 3 rounds of rope as shown in figure 10.4. What is the total length of rope he must use? Length of rectangular field = 240 m Length of rectangular field = 180 m Perimeter of fGiven: Length of the rectangular field =110 mBreadth of the rectangular field =85 mPerimeter of the rectangular field =2(l+b)=2(110+85)=2×195Perimeter of the rectangular field =390 m 2Cost to fence the field per metre = Rs. 25Cost to fence the field 390 metre = Rs. 25×390=Rs.9,750‬∴ Cost of fencing the field =Rs.9750. Bulbul runs around a rectangular park with length 60 m and breadth 45 m. Who covers less distance? Answer: Given that, Length of the square park = 75m Length and breadth of the rectangular park is 60 m and 45m respectively . Therefore, The perimeter of the square park = 4 75 =300 mThe breadth is $30m$ and $30 = 2 \times 3 \times 5$. To find the length of the longest rod which can measure the length and breadth of the field exactly we need to find the H.C.F of the length and breadth of the rectangle because H.C.F. is the greatest number which divides each of the two numbers.Dec 06, 2021 · Transcript. Example 20 A rectangular park is 45 m long and 30 m wide. A path 2.5 m wide is constructed outside the park. Find the area of the path. Here, Area of path = Area of larger rectangle − Area of smaller rectangle Finding length and breadth of both rectangles Smaller rectangle Length of smaller rectangle = 45 m Breadth of smaller ... Area of rectangle B = length × breadth = lb. Calculation: Let the length and breadth of rectangle B be 'l' and 'b' units respectively. Length of rectangle A = (4/5)l. Breadth of rectangle A = (1/2)b. Area of rectangle A = 4l/5 × b/2 = (2/5)lb. Required percentage = [(2/5)lb]/lb × 100 = 40%. ∴ The area of rectangle A is 40% of the ...Therefore, length of rectangle is 21.5 m and the area is 344 m2. Question 2: Solution: The length of a rectangular park = 2(its breadth) Perimeter = 840 m (Given) Let x be the breadth of a rectangular park then, length of a rectangular park is 2x m. We know, Perimeter of rectangle = 2(Length + Breadth) 840 = 2(Length + Breadth) 840 = 2(2x + x) Transcript. Example 1 Length and breadth of a rectangular field are 50 m and 15 m respectively. Find the ratio of the length to the breadth of the field.Examples based on Finding the cost of fencing of a rectangular field. Example 1. Find the cost of fencing of a rectangular field 65 m long and 55 m wide at ₹ 10 per metre? Explanation. Length of the field = 65 m Breadth of the field = 55 m Perimeter of the field = 2 ( l+b ) units Perimeter of the field = 2 ( 65 + 55 ) mClick Home tab > Draw panel > Rectangle. Find Specify the first corner of the rectangle. Specify the other corner of the rectangle. By Length and Width Click Home tab > Draw panel > Rectangle. Find Specify the first corner of the rectangle. Enter D for Dimensions. Enter the length. Enter the width. Specify the other corner. Note: You are restricted by the length and width values. By Area Click ... Solution : Let the length and breadth of the field be 9x and 5x respectively. Area of the field = 14580 sq.m. We know that, The area of a rectangle of length l and breadth b is l × b. Therefore, Area of the field = ( 9 x) × ( 5 x) 14580 = 45 x 2 14580 45 = x 2 324 = x 2 x = 18 So, length (l) = 9 ( 18) = 162 m Breadth (b) = 5 ( 18) = 90 mArea is measured in square units such as square inches, square feet or square meters. To find the area of a rectangle, multiply the length by the width. The formula is: A = L * W where A is the area, L is the length, W is the width, and * means multiply. A square is a rectangle with 4 equal sides. To find the area of a square, multiply the ... The field is rectangular in shape. Given, length(l) = 90 m and breadth(b) = 45 m Distance travelled by the player is the perimeter of the rectangular ground. ∴ Total distance travelled = 2(l + b) = 2(90 + 45) = 270 mDimensions and Markings for the Field Hockey Pitch. Pitch boundary: The pitch on which field hockey is played has a length of 299 feet, 10 inches (91.4 meters) and a width of 180 feet, 5 inches (55.0 meters). This boundary is marked on the turf and the shorter lines are called backlines. Centerline: Breadth $= 2 x = 2 (45) = 90\ m$ Area of the rectangle $=$ Length $\times$ Breadth $=135\times90\ m^2$ $=12150\ m^2$ The area of the rectangle is $12150\ m^2$. 1. Related Doubts. The length and breadth of a rectangular field are in the rate you 5: 2: if the perimeter of the field is 140 metre find the area of the rectangle...